35p^2=255p+200

Solution for 35p^2=255p+200 equation:

35p^2=255p+200

We move all terms to the left:

35p^2-(255p+200)=0

We get rid of parentheses

35p^2-255p-200=0

a = 35; b = -255; c = -200;
Δ = b2-4ac
Δ = -2552-4·35·(-200)
Δ = 93025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{93025}=305$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-255)-305}{2*35}=\frac{-50}{70}
=-5/7
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-255)+305}{2*35}=\frac{560}{70}
=8
$